Wednesday 11 June 2008

The Official SAT Question of the Day™

Read the following SAT test question, then click on a button to select your answer.


If a number is chosen at random from the set {–10, –5, 0, 5, 10}, what is the probability that it is a member of the solution set of both 3x – 2 < 10 and x + 2 > –8?

A 0
B 1/5
C 2/5
D 3/5
E 4/5

Answer is C

Here's Why:

If 3x – 2 < 10 and x + 2 > –8, then –10 < x < 4. The numbers from the listed set that satisfy these inequalities are –5 and 0. There are five elements in the listed set, so the probability of a number chosen at random from the set being a member of the solution set of both inequalities is .


Difficulty: Medium
Question Type: Standard Multiple Choice

(Mathematics)

No comments: